How to run a Java Application from Bash Script

As one that seldom finds himself having to run Java Applications from a Unix Bash Script, I thought it would be helpful to share the appropriate commands i use to execute the code and to notify the user of success or failure. For reference the folder structure I use is:

app_name
- lib
- config

where the lib folder contains all necessary jar files to run the application, and the config folder contains any properties or configuration files passed as run time arguments

#### CMD LINE ?????? ==========================

nohup java.jar.sh &

#### CMD LINE ?????? ==========================

Writing the script

1. Specify the script is a bash script

   			#!/bin/bash
   	

2. Define SUCCESS and FAILURE variables

   			FAILURE=1
   	SUCCESS=0
   	

3. Define the appdirectory

   			APP_HOME=/tmp/app
   	

4. Define the lib folder variable

   			LIB=${APP_HOME}/lib/
   	

5. Define the classpath variable. This is a : seperated list of jars needed by the application

   			CP=${LIB}abc.jar:${LIB}xyz.jar
   	

6. Define java home

   			APP_JAVA_HOME=/usr/jdk/instances/jdk1.5.0
   	

7. Execute the Application with any arguments and java settings

   			${APP_JAVA_HOME}/bin/java -ms256m -cp "${CP}"
   	com.mdibtz.TestApp "${APP_HOME}/config/config.properties"
   	

8. Test for Failure

   			if [ $? -ne 0 ]
   	then
   	exit ${FAILURE}
   	fi
   	

9. Success Logic if needed

   			exit ${SUCCESS}
   	

Complete Script

#!/bin/bash
FAILURE=1
SUCCESS=0
APP_HOME=`pwd`
LIB=${APP_HOME}/lib/
CP=${LIB}activation-1.1.jar:${LIB}mail-1.4.jar
APP_JAVA_HOME=/usr/jdk/instances/jdk1.5.0
${APP_JAVA_HOME}/bin/java -ms256m -mx768m -cp "${CP}"
com.mdbitz.TestApp "${APP_HOME}/config/config.properties"
if [ $? -ne 0 ]
then
echo "AppFailed during run"
exit ${FAILURE}
fi
echo "App successfully run"
exit ${SUCCESS}